Question: For the reaction KClO3 KCl+3/2O2 assign oxidation numbers to each element on each side of the equation. K in KCIO3= CI in KCIO3= O in KCIO3= K in KCI= CI in KCI= Which element is oxidized?

Potassium chlorate (KClO3) solid dissolves into water to form potassium (K+)and chlorate (ClO3−)ions according to the following balanced equation: KClO3 ( s)→K+ (aq)+ClO3− (aq)ΔHrxn∘=+41.3 kJ …

Jan 1, 2026 · For the following reaction KClO3 --> KCl + 3/2 O2 assign oxidation states to each element on each side of the equation. Reactants Products K CL O Number NumberNumberNumber Number …

Question: Potassium chlorate, KClO3, decomposes into potassium chloride, KCl, and oxygen, O2, when heated, as shown in the equation: 2KC10, (s) → 2KC1 (s)+302 (g) The initial mass of potassium …

Given: The unbalanced equation KClO3 --> KCl +O2 To balance the equation, we have to ensure that the number of atoms of each element on both the sides are … View the full answer Previous …

Here’s how to approach this question Calculate the molar mass of potassium chlorate (KClO3) and then use it to find the number of moles of KClO3 by dividing the given mass of KClO3 by its molar mass.

Question: Given the following equation, 2 KClO3 2 KCl+3 O2 how many moles of O2 can be produced from 8.60 moles KClO3? Report your answer with three significant figures

B) calculate the number of moles and the mass of KClO3 originally present in the test tube C) if the original mass of the sample was 4.39 g A test tube containing a mixture of KCl, KClO3, and MnO3 …

Question: Solid Potassium chlorate (KClO3) decomposes into potassium chloride and oxygen gas when heated. How many moles of oxygen form when 55.8 gKClO3 completely decompose?

A1. Reaction of Potassium Chlorate and Sugar (Sacrificial Gummy Bear) The reaction of potassium chlorate and sugar is a combustion reaction, in which the sugar (in the gummy bear) is being …